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x^2-68x+184=0
a = 1; b = -68; c = +184;
Δ = b2-4ac
Δ = -682-4·1·184
Δ = 3888
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3888}=\sqrt{1296*3}=\sqrt{1296}*\sqrt{3}=36\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-68)-36\sqrt{3}}{2*1}=\frac{68-36\sqrt{3}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-68)+36\sqrt{3}}{2*1}=\frac{68+36\sqrt{3}}{2} $
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